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Once the card is installed, it is a good idea to double-check that the card is installed correctly and to see how much free space is available (see Figure 20-2). Follow these steps to do so: 1. Use the Trackpad to glide to the Options icon and click it. You may need to press the Menu key to the left of the Trackpad to see this icon if it is not visible. You can also press the letter O if you have your hotkeys turned on.

The traditional selectivity mechanism has produced a value that is smaller than 1/(number of rows in table), so one of the other figures has been used in this case the selectivity of the fully utilized P_PK index Using concatenated index cardinality for table PARENT Revised join selectivity: 10000e-004 = 79445e-007 * (1/10000) * (1/79445e-007) Join Card: 075 = outer (6801) * inner (11005) * sel (10000e-004) We now move on to the sort/merge join In this example, we try one mechanism for the SM Join A little lower down is an example where we try two different options for the SM Join Historically, the cost of a sort/merge join has shown some bizarre statistics in particular the relationship between the figures that went into the I/O cost per pass and the Total I/O sort cost seemed to be based on an unusual rationale.

TIP: Pressing the first letter of an entry in the Options screen (or in menus) will jump to the first entry in the list, starting with that letter. So pressing M will jump to the first entry starting with M, while pressing it a second time will jump to the next entry that starts with M.

The critical calculations are in the Row size (sum of relevant average column lengths), and the Total Rows (computed cardinality) for each table Oracle works out the CPU cost of sorting these rows, and the possible volume of I/O that will need to take place if the memory requirement exceeds the limit Since we are using pga_aggregate_target here, and have a very small.

cpp using namespace System; interface class I1 { void f(); }; interface class I2 { void f(); }; ref class R : I1, I2 { public: virtual void f() { Console::WriteLine("R::f"); } }; int main() { R^ r = gcnew R(); r->f(); // R::f() implements both I1's f and I2's f } The name conflict in Listing 9-8 is not an error, and the output is as you would expect:.

Look at the Total Space value listed at the bottom of the screen. A 4GB card will read about 3.7MB (1GB equals about 1,000 MB). If you see that number, all is good.

pair of sorts, the Area size: is the _smm_min_size (0.1% of the 200MB we have for the pga_aggregate_target), and the Max Area size: is the _smm_max_size (5% of the target). In this case, the data to be sorted from both tables is very small, so there is no I/O cost. (You can also see that there is no estimated Total Temp space used:.) The cost of the join is therefore Outer Outer Inner Inner table table table table data sort data sort acquisition cost + cost (CPU only in this case) + acquisition cost + cost (CPU only in this case)

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